x^2+105x-2500=0

Solution for x^2+105x-2500=0 equation:

x^2+105x-2500=0

a = 1; b = 105; c = -2500;
Δ = b2-4ac
Δ = 1052-4·1·(-2500)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21025}=145$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-145}{2*1}=\frac{-250}{2}
=-125
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+145}{2*1}=\frac{40}{2}
=20
$